Question

a man goes 9 metre due north and then 12 metre due east how far is he from the starting point​

Answer 1

Step-by-step explanation:

(12)^2 + (9)^2 = (distance from starting point)^2

{ by using Pythagoras}

144+81 = (distance from..)^2

√225 = distance

distance from starting point is = 15m

Answer 2

Step-by-step explanation:

$gose \: to \: north = 9m \: \: \\ \\ gose \: to \: east = 12 \: \\ \\ distanc = \sqrt{9 {}^{2} + 12 {}^{2} }$

$\sqrt{81 + 144}$

$\sqrt{225} = 15 \: meter$