A man goes from A to B at v1 speed and return from B to A at v2 speed. Find average speed.
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Answer:
2(V1V2)/(V1+V2)
Explanation:
speed : A to B : V1
speed : B to A : V2
distance : d ( same in both cases)
time t1 = d/V1
time t2 = d/V2
total distance : D = d + d = 2d
total time : t = t1 + t2 = d(V1+V2)/(V1V2)
avg speed = D/t = 2(V1V2)/(V1+V2)
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