Physics, asked by soumyadipdas68, 2 months ago

A man goes from his home to the grocery
shop at a speed of 6 km/h and returns at
a speed of 9 km/h. If the distance from his home to shop is 900m,calculate the total time (in minutes) and (in hours if you can)that he spends travelling his home to the shop and back.​

Answers

Answered by rsagnik437
134

Answer :-

→ Total time [in minutes] = 15 minutes

→ Total time [in hours] = 0.25 hour

Explanation :-

We have :-

• Speed during first journey = 6 km/h

• Speed during return journey = 9 km/h

• Distance = 900 m = 0.9 km

________________________________

For first journey :-

⇒ Time = Distance/Speed

⇒ t₁ = 0.9/6

⇒ t₁ = 0.15 h

For return journey :-

⇒ Time = Distance/Speed

⇒ t₂ = 0.9/9

⇒ t₂ = 0.1 h

________________________________

Total time taken (in hours) :-

= t₁ + t₂

= (0.15 + 0.1) h

= 0.25 h

Total time taken (in minutes) :-

⇒ 1 hour = 60 mins

⇒ 0.25 hour = 0.25 × 60

15 mins

Answered by Anonymous
115

Given :-

A man goes from his home to the grocery

shop at a speed of 6 km/h and returns at

a speed of 9 km/h. If the distance from his home to shop is 900m,

To Find :-

Total time

Solution :-

We know that

1000 m = 1 km

900 m = 900/1000 = 0.9 km

We know that

Time = Distance/Speed

Time = 0.9/6

Time = 0.15 hours

Again

Time' = Distance'/Speed'

Time' = 0.9/9

Time' = 0.10 hours

Now

The total time taken = Time + Time'

Total time = 0.15 + 0.1

Total time = 0.25 hours

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