A man goes from his home to the grocery
shop at a speed of 6 km/h and returns at
a speed of 9 km/h. If the distance from his home to shop is 900m,calculate the total time (in minutes) and (in hours if you can)that he spends travelling his home to the shop and back.
Answers
Answer :-
→ Total time [in minutes] = 15 minutes
→ Total time [in hours] = 0.25 hour
Explanation :-
We have :-
• Speed during first journey = 6 km/h
• Speed during return journey = 9 km/h
• Distance = 900 m = 0.9 km
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For first journey :-
⇒ Time = Distance/Speed
⇒ t₁ = 0.9/6
⇒ t₁ = 0.15 h
For return journey :-
⇒ Time = Distance/Speed
⇒ t₂ = 0.9/9
⇒ t₂ = 0.1 h
________________________________
Total time taken (in hours) :-
= t₁ + t₂
= (0.15 + 0.1) h
= 0.25 h
Total time taken (in minutes) :-
⇒ 1 hour = 60 mins
⇒ 0.25 hour = 0.25 × 60
⇒ 15 mins
Given :-
A man goes from his home to the grocery
shop at a speed of 6 km/h and returns at
a speed of 9 km/h. If the distance from his home to shop is 900m,
To Find :-
Total time
Solution :-
We know that
1000 m = 1 km
900 m = 900/1000 = 0.9 km
We know that
Time = Distance/Speed
Time = 0.9/6
Time = 0.15 hours
Again
Time' = Distance'/Speed'
Time' = 0.9/9
Time' = 0.10 hours
Now
The total time taken = Time + Time'
Total time = 0.15 + 0.1
Total time = 0.25 hours