Question

_A MAN GOES JORHAT TO DIBRUGARH 30KMPH RETURNS DIBRUGARH TO JORHAT 40KMPH AND AGAIN JORHAT TO DIBRUGARH 45KMPH. THE AVERAGE SPEED OF MAN IS_

Answer 1

Answer:

35.33 kmph

Explanation:

so first we need the distance between  jorhat to dibrugarh whiah is 139 then we find the time taken that is distance/time so it is 139/30=4.63 hours then he goes back at a speed of 40 kmph so it will be 139/40=3.47 hours then he goes baback again at a speed of 45 kmph so it will be 139/45 = 3.08 hours then we find total distance travelled which is  139 * 3  = 417 then we find avg speed by  doing total time/total distance =417/ 4.63+3.47+3.08  =35.33 km ph

so the ans is 35.33 kmph

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