Question

A man goes to gym and loses 8% of weight. If he lost 6Kg and 560g, find how much he weighted earlier ?​

Answer 1

Explanation:

Let the weight earlier be x.

Lost weight is 6kg 560g, which can also be written as 6560g.

Given,

$\frac{8}{100}x=6560$

$x=6560\times\frac{100}{8}=820\times100$

∴ $x=82000$

Hence, his weight earlier was 82000 g or 82 kg.

Answer: 82kg

I hope this helps. :D

Answer 2

Answer:

6560g

Step-by-step explanation:

let the previous weight of the man be x

weight he lost by by going to gym = 8 % of x = 8 / 100 x = 8x /100 . weight after going to gym = 6 kg 560 gm = 6 × 1000 + 560 = 6560 g .