A man goes to market with speed of 60kmph and return with speed of 20kmph.calculate his average speed and average velocity
Answers
Step-by-step explanation:
Let us assume that the distance covered by the man is x km.
Case 1)
Man goes to market with a speed of 60 km/hr.
Now, Time = Distance/Speed
t1 = x/60 hr ............(1st equation)
Case 2)
Man return with a speed of 20 km/hr.
t2 = x/20 hr ..............(2nd equation)
We have to find the average speed of the man.
Average speed is defined as the ratio of total distance travelled with respect to total time taken. Whereas average velocity is defined as the ratio of total displacement with respect to the total time taken.
Assume that the man starts from home to market. As said in question he goes to market with a speed of 60 km/hr and then returns back. Means his starting and initial points are same.
So, the Displacement of the man is 0 km.
Therefore, the average velocity of the man is 0 km/hr.