A MAN GOES TO TOWN AT 40 KM PER HOUR AND COMES BACK AT 60 KM PER HOUR.WHAT IS THE AVERAGE SPEED
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Answered by
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Let the distance between town and house be X km.
TIme taken to reach the town : X/40 hours
Time taken to come back home : X/60 hours
Total time of travel : X(3+2)/120 = X/24 hours
Average speed = Total distance / total time = 2 X / (X/24) = 48 kmph
TIme taken to reach the town : X/40 hours
Time taken to come back home : X/60 hours
Total time of travel : X(3+2)/120 = X/24 hours
Average speed = Total distance / total time = 2 X / (X/24) = 48 kmph
Answered by
0
let the distance between house and town be x
so time taken to go to town = x/40
and time taken to reach home = x/60
Total distance = x+ x = 2x
So average velocity is distance/time
= 48 kmhr⁻¹
so time taken to go to town = x/40
and time taken to reach home = x/60
Total distance = x+ x = 2x
So average velocity is distance/time
= 48 kmhr⁻¹
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