Question

A man gone 24 m due west and the 10 m due north. How for is he from the starting point
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Answer 1

$\bold{ \red{ \huge{ \large{ \star{ { SolutioN : }}}}}}$

Suppose, the man starts from point O and goes 24 m due west to point A. From here, he goes 10 m due north and stops at B.

In the ∆ we have,

• OA = 24m
• AB = 10m

Applying Pythagoras theorem, we get:

$\pink{ \bold{ \large{ \huge{ OB² = OA² + AB²}}}}$

$\pink{ \bold{ \large{ \huge{OB² = 24^{2} + {10}^{2} }}}}$

$\pink{ \bold{ \large{ \huge{OB² = 576 + 100}}}}$

$\pink{ \bold{ \large{ \huge{OB² = 676}}}}$

$\pink{ \bold{ \large{ \huge{OB = \sqrt{676} }}}}$

$\pink{ \bold{ \large{ \huge{OB =26}}}}$