Question

a man gose to the market away by 3km his time taken is 30 minute what is his speed​

Answer 1

$\large\bf\underline\red{Question ➡} \\ \\ \tt \: a \: man \: goes \: to \: the \: market \: away \: by \: \\ \tt \: 3 \ km \: his \: time \: taken \: is \: 30 \: \\ \tt \: minute \: what \: is \: his \: speed \: ? \\ \\ \\ \large\bf\underline\red{we \: have ➡} \\ \\ \blue\star \: \: \tt \: distance \: covered \: by \: the \: man \: 3 \: km \: \\ \\ \blue\star \tt \: the \: time \: taken \: by \: man \: to \: \\ \tt \: cover \: 3 \: km \: = 30 \: minutes \: \\ \\ \large\bf\underline\red{to \: find \: ➡} \\ \\ \bf ➥ \: speed \: of \: the \: man \: to \: cover \: \\ \bf \: 3 \: km \: \bf in \: 30 \: minutes \: \\ \\ \\ \large\bf\underline\red{formula \: used\: ➡} \\ \\ \mathcal{{\fbox{\fbox{\green{ Speed = distance/time }}}}} \\ \\ \\ \large\bf\underline\red{solution\: ➡} \\ \\ \bf \underline{we \: have :} \\ \\ \tt \: distance \: = 3 \: km \: \\ \tt time \: = 30 \: minutes \: = \frac{1}{2} hrs \\ \\ \rm \underline{put \: these \: values \: in \: the \: above \:} \\ \rm \underline{ formula \: we \: get : } \\ \\ \\ \sf \: speed = \frac{distance}{time} \\ \\ ➣ \sf \: speed \: = \frac{3}{ \frac{1}{2} } \: km/h \\ \\➣ \sf \: speed \: = \frac{3 \times 2}{1} \\ \\➣ \sf \: speed \: = 6 \: km/h \\ \\ \\ \sf \: there fore \: the \: speed \: of \: man \: to \: cover \\ \sf \: 3 \: km \: in \: 30 \: min \: is \:\small{\boxed{\mathfrak\red{\fcolorbox{magenta}{aqua}{6 \: km/h}}}} \\ \\ \\\large\bf\underline\red{additional \: formula \: : ➡} \\ \\ ➣ \: \sf \: speed \: = \frac{distance}{time} \\ \\ ➣ \: \sf \: distance \: = speed \: \times time \\ \\ ➣ \: \sf \: time \: = \frac{distance}{speed} \\ \\ \\\sf\underline\red{know \: more \: about \: speed \: : ➡} \\ \\ ➛ \: \sf \: the \: S.I \: unit \: of \: speed \: =m/s \\ ➛ \: \sf \: speed \: is \:a \: scalar \: quantity \: \\ ➛ \: \sf \: speed \: is \: depends \: upon \: time. \\ ➛ \: \sf \: if \: any \: object \: takes \: more \: \bf \: time \: \sf \: to \\ \sf \: cover \: a \: distance \: then \: \bf \: speed \: \sf \: will \: \\ \sf \: be \: \bf \: less \: \sf \: and \: when \: \bf \: time \: \sf \: taken \: by \: the \: \\ \sf \: object \: is \: \bf \: less \: \sf \: then \: \bf \: speed \: \sf \: will \: \bf \: more \: .$

Answer 2

ANSWER

Average velocity is total displacement upon total time. But his initial and final position are same, so his displacement is zero.

Hence his average velocity is zero.