Question

A man had 16000, part of which he lent at 8% per annum and the rest at 9% per annum simple interest,if the total annual intrest be rs 1340,the money lent at 8% is

Answer 1

AnswEr :

Let the Money lent on 8% p.a. be Rs. x, and Money lent on 9% p.a. be Rs.(16000 - x).

$\qquad \quad \sf{Rs. \:16000} \\ \qquad \large{\quad\swarrow \qquad\searrow} \\ \quad\underline{\tt1st \:part} \qquad\underline{ \tt2nd \:part} \\ \quad\sf{Rs.\:x}\qquad \qquad\sf{Rs.(16000 - x)}$

$\rule{300}{1}$

• Let's Head to the Question Now :

$\longrightarrow \tt SI_{on \:8\% \:p.a.} + SI_{on \:9\% \: p.a.} = Rs. 1340 \\ \\\longrightarrow \tt \dfrac{PRT}{100} + \dfrac{prT}{100} = Rs. 1340 \\ \\\longrightarrow \tt \dfrac{x \times 8 \times 1}{100} + \dfrac{(16000 - x) \times 9 \times 1}{100} = 1340 \\ \\\longrightarrow \tt \dfrac{8x}{100} + \dfrac{144000 - 9x}{100} =1340 \\ \\\longrightarrow \tt \dfrac{8x + 144000 - 9x}{100} = 1340 \\ \\\longrightarrow \tt144000 - x = 134000 \\ \\\longrightarrow \tt144000 - 134000 = x \\ \\\longrightarrow \large \boxed{ \blue{\tt x = Rs. \: 10000}}$

⠀

∴ Money lent on 8% p.a. is Rs. 10,000.

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Answer 2

Answer:

$\bold\red{Money\:lent\: at \:8\%=Rs.10000}$

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N O W :-

Let the lent at 8% per annum be 'X'

So, lent at 9% per annum is (16000-X)

According to question now:-

$\rightarrow\tt SI_8\% + SI_9\%=1340$

$\rightarrow\tt Prn + PRn =1340$

$\rightarrow\tt X\times 8\%\times 1 + (16000-X)\times 9\%\times 1 =1340$

$\rightarrow\tt 0.08X + (1440 -0.09X) =1340$

$\rightarrow\tt -0.01X +1440 = 1340$

$\rightarrow\tt 0.01X =1340-1440$

$\rightarrow\tt X =\frac{-100}{-0.01}$

$\rightarrow\tt X =Rs.10000$

So,money lent at 8% = Rs.10000.

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#BAL