Question

a man had 3 animals.horse+cow eats the food in 40 days .and cow+sheep eat the foods in 60 days and horse+sheep eat the food in 90 days then cow +sheep+horse=??please explain with answer ​

Answer 1

Answer:

horse -x

cow-y

sheep-z

then .

....1......x+y=40

.....2.....y+z=60

...,...3...z+x=90

Step-by-step explanation:

1 and 3

x+y = 40

x+z = 90

_-__-___-______

y-z = -50.....(4)

with eqn 2 and 4

y+z =60

y-z = -50

______________

2y =10

y = 5

and hence by value of y in eqn 1. x=35 & in eqn 3 .. z=55..

hence x+y+z = 95