Question

A MAN HAD 3 SONS AND SOME DIAMONDS.
ONE DAY HE TOLD HIS SONS THAT "TOMORROW I WILL DISTRIBUTE ALL
THE DIAMONDS EQUALLY AMONG YOU THREE."
AT THE NIGHT THE ELDEST SON WAKE WAKE UP AND DIVIDED THE
DIAMONDS IN THREE EQUAL PARTS AND TOOK 1 PART AND LEFT THE
OTHERS
AFTER SOME TIME THE MIDDLE SON WAKE UP AND REDISTRIBUTED THE
LEFT OVER DIAMONDA IN THREE PARTS AND TOOK 1 PART AND LEFT
THE OTHER DIAMONDS.
AFTER SOME TIME THE YOUNGER SON WAKE UP AND REDISTRIBUTED
THE LEFT OVER DIAMONDA IN THREE PARTS AND TOOK 1 PART AND
LEFT THE OTHER DIAMONDS.
AT MORNING THE FATHER REDISTRIBUTED THE LEFT OVER DIAMONDS IN
THREE PARTS AND GAVE ONE PART TO EACH SON.
AFTER THE DISTRIBUTION 1 DIAMOND WAS LEFT.
TELL HOW MANY DIAMONDS WERE IN THE BEGINNING.
PLZ SOLVE THIS FOR ME​

Answer 1

there will be 7 diamonds as per my calculations