A MAN HAD 3 SONS AND SOME DIAMONDS.
ONE DAY HE TOLD HIS SONS THAT "TOMORROW I WILL DISTRIBUTE ALL THE DIAMONDS EQUALLY AMONG YOU THREE."
AT THE NIGHT THE ELDEST SON WAKE WAKE UP AND DIVIDED THE DIAMONDS IN THREE EQUAL PARTS AND TOOK 1 PART AND LEFT THE OTHERS.
AFTER SOME TIME THE MIDDLE SON WAKE UP AND REDISTRIBUTED THE LEFT OVER DIAMONDA IN THREE PARTS AND TOOK 1 PART AND LEFT THE OTHER DIAMONDS.
AFTER SOME TIME THE YOUNGER SON WAKE UP AND REDISTRIBUTED THE LEFT OVER DIAMONDA IN THREE PARTS AND TOOK 1 PART AND LEFT THE OTHER DIAMONDS.
AT MORNING THE FATHER REDISTRIBUTED THE LEFT OVER DIAMONDS IN THREE PARTS AND GAVE ONE PART TO EACH SON .
AFTER THE FINAL DISTRIBUTION 1 DIAMOND WAS LEFT .
TELL HOW MANY DIAMONDS WERE IN THE BEGINNING.
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Answer:
at the begining you can take any multiple of 3
Answered by
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Answer:
you can take any multiple of 3
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