Question

A man had RS 4000,part of which he lent at 5% and the rest at 4% .The whole interest received was RS 190. How much did he lent at 4% ?

Answer 1

Step-by-step explanation:

Let Rs x lent at 5% interest and Rs y at 4% interest.

Total money had Rs 4000

Therefore,  x + y = 4000     -----------(1)

Interest on Rs x = 5% of x

                          = 0.05x

Interest on Rs y = 4% of y

                          = 0.04x

Total interest received = Rs 190

0.05x + 0.04y = 190   -----------------(2)

using eq(1) and eq(2) solve for x and y

By elimination method, multiply first equation by -0.04

-0.04x -0.04y = -160

0.05x + 0.04y = 190

               0.01x = 30

                      x = 3000

Put x into x + y = 4000

3000 + y = 4000

             y = 1000

Hence, Rs 1000 lent at 4%

HOPE IT WILL HELP YOU

Answer 2

AnswEr :

Let the First Part lent at 4% be Rs. n and, Second Part lent at 5% be Rs. (4000 – n).

$\bigstar\:\boxed{\sf Simple \:Interest = \dfrac{Principal \times Rate \times Time}{100}}$

$\rule{150}{1}$

$\underline{\bigstar\:\textsf{According to the Question Now :}}$

$:\implies\sf SI_1 + SI_2 = Total \:Interest\\\\\\:\implies\sf \dfrac{P_1R_1T}{100}+\dfrac{P_2R_2T}{100}=Rs.\:190 \\\\\\:\implies\sf \dfrac{n \times 4 \times 1}{100}+\dfrac{(4000 - n) \times 5 \times 1}{100}=Rs.\:190\\\\\\:\implies\sf \dfrac{4n}{100}+\dfrac{20000 - 5n}{100}=Rs.\:190\\\\\\:\implies\sf \dfrac{4n + 20000 - 5n}{100}=Rs.\:190\\\\\\:\implies\sf20000 - n = 190 \times 100\\\\\\:\implies\sf20000 - n = 19000\\\\\\:\implies\sf20000-19000 = n\\\\\\:\implies\boxed{\sf n = Rs. \:1000}$

⠀

$\therefore\:\underline{\textsf{Money lent at 4\% wil be \textbf{Rs. 1000}}}$