A man had some milk. When he sold 3/4 parts of the quantity of milk, 15 / was left. How much milk did he have in the beginning? could you please explain step by step. pleaseeeeeeeeeeeeeeeee
Answers
Answer:
A container contains 40 litres of milk. From this container, 4 litres of milk were taken out and replaced by water. This process was repeated further two times. How much milk is now contained by the container?
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Let me tell you a cool trick/formula to solve such problems.
Let there be 'N' litres of milk initially.
'P' litres are taken out & replaced by water..........( for the 1st time )
'P' litres are taken out & replaced by water..........( for the 2nd time )
'P' litres are taken out & replaced by water..........( for the 3rd time )
'P' litres are taken out & replaced by water..........( for the 4th time )
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'P' litres are taken out & replaced by water..........( for the 'n'th time )
Then,
Milk = ( 1 - P/N )^n
------ -----------------
Water 1 - ( 1 - P/N )^n
Milk = Milk = ( 1 - P/N )^n
--------- - --------------
Solution Milk + Water
Water = Water = 1 - ( 1 - P/N )^n
--------- - --------------
Solution Milk + Water
For your Question:
N=40
P=4
n=3
Milk (M) = ( 1 - 4/40)^3 = 0.9^3
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Solution(40)
=> M = 40* (0.9)^3 = 29.16
Answer:
20 litre
Step-by-step explanation:
20 litre is the right answer of this question