Math, asked by sunitayadav6856, 3 months ago

A man has₹(15a-13b) he spends ₹(a+b) on the rent of his house ₹(3a-7b) on the education of the children ₹ (4a-3b) on the treatment of his parents and ₹(5b+4a) on other expences.find the sum of money left with him. ( step by step explanation)

Answers

Answered by kumarguptaraj87
0

Step-by-step explanation:

Total money = Rs(15a-3b)

money he spend= Rs(a+b) + Rs(4a-3b) + Rs(5b+4a)

= Rs(9a+3b)

money left with him now = Rs(15a-3b) - Rs(9a+3b)

= Rs(6a-6b)

Answered by pathakambika65
0

Answer:

₹8+27

Step-by-step explanation:

man has ₹( 15a-13b)

he spend on rent = ₹(a+b)

on education= ₹(3a-7b)

on treatment= ₹(4a-3b)

on other expences = ₹(5b-4a)

sum of money left with him = sum of all money spend - total number of money.

(a+b)+(3a-7b)+(4a-3b)+(5b-4a)

a+b+3a-7b+4a-3b+5b-4a

a+3a+7a-4a +b -7b-3b+5b

7a+14b

so, (15a-13b)-(7a+14b)

15a-13b-7a-14b

15a-7a-13b-14b

₹ 8 + 27 left with him.

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