Question

A man has 2.75 Rs in 10 paisa and 25 paisa coins. If the ten paisa coins exceed the 
number of twenty five paisa coins by three, how many coins of each does he have?

Answer 1

25 paise coins are 7 and 10paise coins are 10

Answer 2

Let no. of 25 paisa coins be x.
Then, no. of 10 paisa coins = (x+3)
Total money = Rs. 2.75.......................(i)
Total cost of 25 paisa coins = x*25/100 Rs. = x/4 Rs.
Total cost of 10 paisa coins = (x+3)*10/100 Rs. = (x+3)/10
Total money = Rs. x/4 + (x+3)/10........(ii)
Therefore,
               x/4 + (x+3)/10 = 2.75                               [From equation (i) and (ii)]
               (5x + 2x + 6)/20 = 2.75
               (7x + 6) = 2.75 * 20
               (7x + 6) = 55
               7x = 49
               x = 7
Therefore,
He has no. of 25 paisa coins = x = 7
and He has no. of 10 paisa coins = (x+3) = 7+3 =10

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