A man has 2 sons and a daughter . the sum of the ages of his 2 sons and one daughter is equal to the age of the father . In 15 yrs the sum of ages of his children will be one and a half times their fathers age then . what is the fathers age now ?
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Let Father's age = F, 1st Son's age = S1 and 2nd son's age = S2 and daughter's age = D
We have two conditions given in the question.
F = (S1 + S2 +D) -------------- (i)
After 15 years,
F + 15 = (S1 + 15 + S2 + 15 + D + 15)
1.5F = S1 + S2 + D + 45
OR
F = (S1 + S2 +D +45)/1.5 -------------- (ii)
Equating (i) and (ii), we get
S1 +S2 + D = (S1 + S2 +D +45)/1.5
1.5S1 + 1.5S2 + 1.5D = S1 + S2 + D +45
0.5S1 + 0.5S2 + 0.5D = 45
Now dividing both sides by 0.5, we get:
S1 + S2 + D = 90
Putting this value in (i), we get F = 90
So father's age is 90 years.
We have two conditions given in the question.
F = (S1 + S2 +D) -------------- (i)
After 15 years,
F + 15 = (S1 + 15 + S2 + 15 + D + 15)
1.5F = S1 + S2 + D + 45
OR
F = (S1 + S2 +D +45)/1.5 -------------- (ii)
Equating (i) and (ii), we get
S1 +S2 + D = (S1 + S2 +D +45)/1.5
1.5S1 + 1.5S2 + 1.5D = S1 + S2 + D +45
0.5S1 + 0.5S2 + 0.5D = 45
Now dividing both sides by 0.5, we get:
S1 + S2 + D = 90
Putting this value in (i), we get F = 90
So father's age is 90 years.
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