a man has 21rupees in form of 50paisa and 25paisa coins if the the total number of coins are 52, find the number of coins of each type .
Answers
Answer:
32-50P coins
20-25P coins
Answer:
The number of coins 50 paise are 32 and number of coins of 25 paise are 20 .
Step-by-step explanation:
Let us assume that the number of 50 paise coin be x .
Let us assume that the number of 25 paise coin be y .
As given
A man has Rs 21 in the form of 50 paise and 25 paise coins.
As 0.01 Rupee = 1 paise
Than the equation becomes
0.01 × 50x + 0.01 × 25y = 21
Simplify the above
50x100+25y100=21\frac{50x}{100}+ \frac{25y}{100} = 21
100
50x
+
100
25y
=21
50x + 25y = 2100
If the total no of coins are 52.
Than the equation becomes
x + y = 52
Two equations are
x + y = 52
50x + 25y = 2100
Multiply x + y = 52 by 50 and subtracted from 50x + 25y = 2100 .
50x - 50x + 25y - 50y = 2100 - 2600
-25y = -500
y=50025y = \frac{500}{25}y=
25
500
y = 20
Putting this value in x + y = 52 .
x + 20 = 52
x = 52 -20
x = 32
Therefore the number of coins 50 paise are 32 and number of coins of 25 paise are 20 .