Question

A man has 3 ball pens and 5 ink pens in how many different ways can he select either ball pen or ink pen

Answer 1

Answer:

Step-by-step explanation:probability of getting either ball pens or ink pens refers to the addition of both the probability of getting a ball pen and an ink pen.

So,

Total no. Of ball pens =3

Total no. Of ink pens=5

Probability of choosing one ball pen out of the three =1/3 (numerator is the amount you plan to pick ,denominator is the total no.)

P(ink pens) = 1/5

P( ink pens + ball pens)= 1/3+1/5= 8/15

Thank you, I hope this helps .

Help me too please!!

Answer 2

Given: A man has 3 ball pens and 5 ink pens.

To find: How many different ways can he select either ball pen or ink pen.

Solution:

In order to solve the given question, the concept of combinations can be used. A combination can be calculated by using the following formula.

$^{n}C_{r} = \frac{n!}{r!(n-r)!}$

Here, n is the total number of elements given and r is the number of elements that need to be selected. Thus, the number of ways to select a ball pen is calculated as shown below.

$^{n}C_{r} = \frac{8!}{3!(8-3)!}$

       $=56$

Similarly, the number of ways to select an ink pen is calculated as shown below.

$^{n}C_{r} = \frac{8!}{5!(8-5)!}$

       $= 56$

Since the number of ways to select either ball pen or ink pen is to be calculated, the following is done.

$56+56= 112$

Therefore, he can select either ball pen or ink pen in 112 ways.