A man has 3 daughter and 4 identical
doughnuts to distribute among them. In how
many ways can he distribute these
doughnuts without making parts of any one
of them and each daughter getting atleast
one?
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Given: A man has 3 daughters and 4 identical
doughnuts to distribute among them such that he can distribute these doughnuts without making parts of any one of them and each daughter getting at least one
To find: Total number of ways
Solution: Here we need to distribute 4 doughnuts among 3 daughters in such a way that each daughter will get at least 1 doughnut
So we can say that out of 4 if we will distribute 3 doughnuts among all the daughters and will be left with 1 doughnut.
So we need to find ways in which we can distribute 1 doughnut among 3 daughters
So that will be 3C1 = 3
So the total number of ways in which we can distribute the doughnuts will be 3.
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