A man has 3 sons, 2 daughters and a wife. they divided a sum of rs 19000 among themselves such that each daughter got 1.5 times the amount received by each son and his wife received 600 less than each son. what is the total amount (in rs) received by the 3 sons together? solution
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hey friend!
let the amount of son X
then
there are three son
so
3 son amount = 3x
each doughter got 1.5 times rs than her brother
thus
= 1.5x
there's two daughters
so
= 2× 1.5x = 3x
and
his wife 600 less than each son
so
= X -600
nOw
3x +3x +X -600 = 19000
7x = 19000+600
7x = 19600
X = 19600/7
X = 2800
Thus each son have 2800 rs
& Three son have => 3×2800 = 8400Rs
☺☺☺☺
let the amount of son X
then
there are three son
so
3 son amount = 3x
each doughter got 1.5 times rs than her brother
thus
= 1.5x
there's two daughters
so
= 2× 1.5x = 3x
and
his wife 600 less than each son
so
= X -600
nOw
3x +3x +X -600 = 19000
7x = 19000+600
7x = 19600
X = 19600/7
X = 2800
Thus each son have 2800 rs
& Three son have => 3×2800 = 8400Rs
☺☺☺☺
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