Question

A man has 3 sons and 6 schools within his reach. In how many ways he can send his sons to

schools if no two of his sons are to read in the same school?

(a) 120 (b) 240

(c) 360 (d) 60​

Answer 1

Answer:

120

Step-by-step explanation:

Using Fundamental Principal of Counting

First son can be send in any of the 6 school in 6 ways.

Second son can be send in any of the 5 remaining schools in 5 ways.

Third son can be send in any of the remaining 4 schools in 4 ways.

so total number of ways = 6×5×4 = 120