Question

A man has 350 watches .he sells w watches everyday. write an algebraic expression to solve the number of watches he would be left after y week

Answer 1

$\textbf{Given :} \\ \\ \textbf{A man has 350 watches.} \\ \\ \textbf{He sells w watches everyday.} \\ \\ \textbf{To find, } \\ \\ \textbf{How many watches will be left with him after y week.} \\ \\ \textbf{Main solution :-} \\ \\ \textbf{No. of watches he sells everyday = w }\\ \\ \textbf{No. of days in y no. of week = 7 × y = 7y }\\ \\ \textbf{Total days = 7y }\\ \\ \textbf{Total watches sold by him during these days = 7y × watches sold per day = 7y × w = 7yw }\\ \\ \textbf{Watches left = Total watches - watches sold by him}\\ \\ \textbf{Substituting the values ,}\\ \\ \textbf{Watches left = 350 - 7yw }\\ \\ \textbf{ = 7(50 - yw ) }$

Answer 2

HEY MATE HERE IS YOUR ANSWER

A man has 350 watches

$he \: sells \: {w} \: watches \: everyday$
$to \: find \: how \: many \: watches \: will \\ \: be \: left \: with \: him \: after \: y \: weak$
No of watches he sells everyday =w

No of days in Y number of weak = 7×y= 7y

:. Total days = 7y

Total watches sold by him during these day = 7y × watches sold per day=(y) (w)

$watches \: left \: = \: total \: watches - \: watches \: solved \: by \: him$


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