Question

a man has 5 sons the sum of the ages of 5 sons being equal to the age of the father.in 12 years time the sum of the ages of the sons will be doubled that the father. what is the father age now

Answer 1

Let the present age of 1st son : A years
the present age of 2nd son : B years
the present age of 3rd son : C years
the present age of 4th son : D years
the present age of 5th son : E years

Therefore, the equation states that

A + B + C + D + E = Father's age

After 12 years the sum of 5 sons age is equal to double the father’s age
(A + 12) + (B + 12) + (C + 12) + (D + 12) + (E + 12) = 2(Father's age)
(A + B + C + D + E) + (5 x 12) = 2(Father's age)
= (Father's age) + 60 = 2(Father's age)
= 60 = 2(Father's age) - (Father's age)
= 60 = Father's age
Therefore, Father's age is 60 Years

Answer 2

Answer:

Answer is 36

Step-by-step explanation:

Let the 5 Son's Age: A, B ,C , D , E

LET FATHER'S AGE= X YEARS

A+B+C+D+E= X......(1)

A+12+B+12+C+12+D+12+E+12= 2(X+12)

A+B+C+D+E + 60 = 2X +24

USING EQN 1

X+60= 2X +24

60-24= 2X-X

36 = X

THUS ANSWER IS 36

HOPE IT WILL HELP YOU!!!