Question

a man has 70 notes in all of rupees 10 and rupees 20 terminations if the total worth of notes is 900 rupees find out the how many notes of each kind does he have​

Answer 1

Given x+y=70. -----(1)

10x+20y=900

x+2y=90. ------(2)

From equation (1) x=70-y put it in eq.(2)

Then 70-y+2y=90

y=20

so x=70-y=70-20=50.

Check:

put value of x & y in eq (1) & (2)

(1)=50+20=70

(2)=10(50)+20(20)=900.

Hope U understood it.

Answer 2

Answer:Let no. of 10 rs. notes be x.

Let no. of 20 rs. notes be y.

Total no.of notes =70

Total money=900rs.

Step-by-step explanation:

x+y=70 .....(i)

10x+20y=900 ......(ii)

In eq (i)

x=70-y ........(iii)

Keeping value of x from eq (iii) in eq.(ii)

10(70-y)+20y=900

700-10y+20y=900

10y=200

y=200/(10)

y= 20 .....(iv)

Keep value of y from eq (iv) in eq(iii)

x=70-20

x=50

No. of 10rs notes is 50 and 20rs notes is 20.

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