Question

a man has 81 cows and 9 sons. the man want to devide the cows equally among his nine sons such that each son get equal amount of milk . Each cow give milk according to its no. For example 8th no. cow give 8 litre milk etc like this . So, how much milk does each son will get??

Answer 1

Answer:

The total number of cows with all the nine people should be:- 81 ÷ 9 = 9 cows.

So, all the nine people should get nine cows each person.

Now, Finding how much total litres of milk is produced by all the cows:-

The cows are numbers from 1 to 81.

Hence, it makes an arithmetic progression.

So, here,

a = 1

d = 1

n = 81

Now, Sn = n/2 (2a + (n - 1)d)

So, Sn = 81/2 (2 + (81 - 1)1)

Sn = 81/2 × (2 + 80)

Sn = 81/2 × 82

Sn = 81 × 41

Sn = 3,321 litres

The Total amount of milk produced by all the cows = 3,321 litres.

Total milk produced by the nine cows that will be given to all the nine people = 3,321 ÷ 9 = 369 litres.

So, all the nine people will get nine cows that will totally produce 369 litres of milk

Answer 2

Step-by-step explanation:

a man have 81 cows with 9 sons

man can divide cows equally among his 9 sons

and equal amount of milk

so he divide 1 son to 9 cows

so 9 sons want 81 cows that he have to divide

we can add the sum of all cows liter of milk

so...

1+2+3+4+5+6+7+8+9+10+11+12+13+14+15..........79+ 80+81

so answer is

3321

so we can give equal amount of milk each of them

3321 ÷ 9

369

so each son get 369 liters of milk

I hope this will help you