Question

A man has a certain number of small boxes to pack into parcles. If he packs 3, 4, 5 or 6 in a parcel, he is left with one over
A)

Answer 1

Answer:

aaaa

Step-by-step explanation:

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Answer 2

Answer:

Min boxes = 61

Step-by-step explanation:

Find the LCM of 3, 4, 5, 6

LCM == 60

To get a remainder of '1', minimum number of boxes == 61

[LCM: using prime factorization

3=3

4=2^2

5=5

6=2x3

Lcm = 2^2 × 3 × 5 = 60]