Question

A man has a mass of 60kg and is moving with 18km/hr. He jumps into a trolley weighing 1quinton which is stationary. Calculate the final velocity of the trolley after the man jumped into the trolley

Answer 1

the velocity of the man is 3

Answer 2

Man

m- 60kg

u - 0m/s

v - 18 km/hr ; 5m/s

Trolley

Weight - 100 kg

u- 0 m/s

According to the Law of Conservation of Momentum;

m1v1 + m2v2 = m1u1 + m2u2

= v(m1 + m2)

60 x 5 + 100 x 0 = (60+100) v

300+0 = 160v

v = 300/160 = 15/8 m/s