a man has an auto rickshaw to cover a certain distance for fare is rupees 84 1st kilometre and rupees 7 for substituent kilometre taking Total distance covered as X kilometre in Total fare is rupees 5 first find a linear equation for this second draw the graph of this equation 3rd a man covers a distance of 16 km and give rupees 150 to the auto driver auto driver set it is not correct amount in written form the balance find the correct amount paid by the auto driver for which value is depicted here by auto driver
Answers
Answer:
Step-by-step explanation:
Kilometer covered = x km
Total fare = y rs
Fare for 1st kilometer = 10 rs
fare per rest km = 7 rs
--> total fare = 10 + 7(total distance - 1km) [we need to subtract 1km bcause he charges 10 rs for first km and we have added it already]
y = 10+7(x-1)
y = 3+7x
7x - y + 3 = 0
--->u can draw the graph easily ,
put 3 values of x , get 3 corresponding values of y
mark these as 3 points on the graph and draw a straight line passing through them
--->Fare for 16 km = 3 + 7(16) = 3 + 112 = 115rs [putting 16km in the above equation]
--> the person gives 150 rs and the total fare is 115rs , so the rickshaw waala will give back 35 rs to him.
---> The autodriver is honest , kind and a nice human
Given,
Total distance = X km
Total fare = Rs. Y
According to given condition, First km = Rs. 10
Therefore remaining distance after 1st km would be (X-1)km.
Fare for remaining distance is Rs.7/km Hence cost would be
7 × (X-1) Rs.
Total cost 10+ 7×(X-1)
Y = 10 + 7X-7
Y=3+7X
Linear equation -- 7X-Y+3=0
(2)
Total distance travelled is 16 km
therefore x=16 km
putting the value of X in above equation we get,
7 (16)-Y+3=0112+3=Y
Y = 115
(3)Now, according to question,y=7x+3(2).
Put x =16 in the above equation,
then we get
y = 7 x 16+3 = 115
So, correct amount for covering 16 km = R s 115.
So,amount paid back by the auto driver =200-115 Rs 85
The values depicted are :honesty, self res pect.
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