A man has belts and handkerchief which are together 40 in no . If he had 5more handkerchief and 5 less belt than the no. Of handkerchiefs becomes four times the no. Of belts. Find the original no. Of each ....
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Saubia Virtuoso
Let the no of handkerchief be x and the no. of belts be y.
x+y=40......(i)
now from the II condition,
(x+5)+(y-5)=40
and (x+5)=4(y-5)
x+5=4y-20
x-4y=-25(ii)
now subtract eqn (ii) from(i) we get,
5y=65
y=13 and x=27 ,these are the original no.s of belts and handkerchiefs.
now if we have 5 more handkerchiefs(x) i.e x=32
and 5 less belts i.e. y=8
we can see no. of handkerchiefs are four times the no. of belts.
Please mark as brainliest
Let the no of handkerchief be x and the no. of belts be y.
x+y=40......(i)
now from the II condition,
(x+5)+(y-5)=40
and (x+5)=4(y-5)
x+5=4y-20
x-4y=-25(ii)
now subtract eqn (ii) from(i) we get,
5y=65
y=13 and x=27 ,these are the original no.s of belts and handkerchiefs.
now if we have 5 more handkerchiefs(x) i.e x=32
and 5 less belts i.e. y=8
we can see no. of handkerchiefs are four times the no. of belts.
Please mark as brainliest
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