Math, asked by madhupradeeppant, 11 months ago

) A man has choice to invest in hundred-rupee shares of two companies A and B .
Shares of company A are available at a premium of 20% and it pays 8% dividend
whereas shares of company B are available at a discount of 10% and it pays 7%
dividend , If the man invests equally in both the companies and the sum of the return
from them is Rs 936 , find how much , in all , does he invest ?

Answers

Answered by danyle
5

Answer:

Step-by-step explanation:

FIRST COMPANY -

Market value of 1 share =Rs. 120=Rs.120

Money invested =Rs. 26400=Rs.26400

Number of shares bought =\dfrac{26400}{120}=  

120

26400

​  

 

                                           =220=220

Dividend of 1 share on Rs.100=5\%Rs.100=5% of Rs. 100=Rs.5Rs.100=Rs.5

Dividend of 220220 shares =220\times 5=Rs.1100=220×5=Rs.1100

Annual return =Rs.1100=Rs.1100

SECOND COMPANY -

Market value of 1 share =Rs. 132=Rs.132

Money invested =Rs. 26400=Rs.26400

Number of shares bought =\dfrac{26400}{132}=  

132

26400

​  

 

                                           =200=200

Dividend of 1 share on Rs.100=6\%Rs.100=6% of Rs. 100=Rs.6Rs.100=Rs.6

Dividend of 200200 shares =200\times 6=Rs.1200=200×6=Rs.1200

Annual return =Rs.1200=Rs.1200

a). So, second company is paying better return.

b). Difference in annual return =1200-1100=1200−1100

                                                  =Rs.100=Rs.100

Hence, solved.

Answered by Ladylaurel
4

Answer:

FIRST COMPANY -

Market value of 1 share =Rs.120

Money invested =Rs.26400

Number of shares bought =

120

26400

=220

Dividend of 1 share on Rs.100=5% of Rs.100=Rs.5

Dividend of 220 shares =220×5=Rs.1100

Annual return =Rs.1100

SECOND COMPANY -

Market value of 1 share =Rs.132

Money invested =Rs.26400

Number of shares bought =

132

26400

=200

Dividend of 1 share on Rs.100=6% of Rs.100=Rs.6

Dividend of 200 shares =200×6=Rs.1200

Annual return =Rs.1200

a). So, second company is paying better return.

b). Difference in annual return =1200−1100

=Rs.100

Hence, solved.

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