Question

a man has five resistors each of value 1/5 ohm .what is the maximam resistance he can obtain by connecting them?

Answer 1

if connected in series then resistance will be 1 ohm. as their equivalent resistance is q
equal to their sum

Answer 2

Answer:

Therefore, the maximum resistance can be created by utilizing five resistors each of $1 / 5 \Omega$ is $1 \Omega$.

Explanation:

We know that total resistance decreases when resistors are linked in parallel.

It is calculated as $1 / R T=1 / R 1+1 / R 2+1 / R 3+1 / R 4+\ldots \ldots . .+1 / R n$

While total resistance rises when resistors are connected in series

It is calculated as $R T=R 1+R 2+R 3+R 4+\ldots \ldots .+R n$

It means, we can get the lowest resistance when all the provided resistors will join in parallel, and maximum resistance can be accepted when all the given resistors choice join in series.

So, for seeing maximum resistance, we have to join all resistors in series.

Here, given $5$ resistors each resistance $1 / 5 \Omega$ or $0.2 \Omega$

Now, placing the value of the resistors in the formula of series connection-

$&R T=0.2+0.2+0.2+0.2+0.2$

$&R T=1.0 \Omega$

Hence, the maximum resistance can be created by utilizing five resistors each of $1 / 5 \Omega$ is $1 \Omega$.

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