A man has five sons whose ages equal to age of father. After 12years the sum of their ages is equal to the twice the age of father
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Answer:
Age of father = 36
Step-by-step explanation:
Let sum of ages of five sons = X and age of father = Y
X = Y
after 12 years, X + 5*12 = 2 (Y+12)
X + 60 = 2Y + 24
ie, Y + 60 = 2Y + 24
Y = 36
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