Question

a man has only 20 paisa coins and 25 paisa coins in his purse. if he has 50 coins in all totaling rs 11.25 how many coins of the does he have

Answer 1

let 20 Paisa coins be x and 25 paise coins be y. therefore according to the question,
x+y=50 ...(1)
20x+25y=1125 ...(2)
now we will solve it by any method out of substitution, elimination or cross multiplication.
(I have done substitution method)
from (1), x=50-y putting x=50-y in (2):
20(50-y)+25y=1125
1000-20y+25y=1125
1000+5y=1125
5y=1125-1000
5y=125
y=125/5
y=25 and x =50-y=50-25=25
thank u , hope it helps!

Answer 2

Suppose number of 20 paisa coins = x
And, number of 25 paisa coins = y

So, total coins => x + y = 50..........eq. 1

Now, total amount of 20 paisa coins = ₹20x
And, total amount of 25 paisa coins = ₹25y

So, total amount in purse=> 20x + 25y = 1125 paise...........eq. 2

Now, we multiply eq. 1 by 20,
Then, 20x + 20y = 1000.....eq. 3

Now, (eq. 2) - (eq. 3)

20x + 25y = 1125
20x + 20y = 1000
On substracting...

5y = 125

y= 25.....◆

Now on putting the value of y in eq. 1..

x +25 = 50

x= 25...◆

So.....number of 20 paisa coins (x) = 25

And, number of 25 paisa coins (y) = 25

I hope it was helpful... please mark as brainliest...