A man has only 20 paise coins and 25 paise coins in his purse. If he has 50 coins in all totalling Rs 11.25, how many coins of each kind does he have?
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Answered by
9
Let no. of 20 paise coins is x and no. of 25 paise coins is y. Then by the given question,
x+y=50 --------------------(1) and
20x+25y=1125 [∵, Rs. 11.25=1125 paise]
or, 4x+5y=225 -----------(2)
Multiplying (1) with 4 we get,
4x+4y=200 ---------------(3)
Subtracting (3) from (2) we get,
y=25
Putting in (1)
x=50-y=50-25=25
∴, x=25, y=25
x+y=50 --------------------(1) and
20x+25y=1125 [∵, Rs. 11.25=1125 paise]
or, 4x+5y=225 -----------(2)
Multiplying (1) with 4 we get,
4x+4y=200 ---------------(3)
Subtracting (3) from (2) we get,
y=25
Putting in (1)
x=50-y=50-25=25
∴, x=25, y=25
Answered by
7
Let the no. Of 20 paise coins be x
Let the no. of 25 paise coins be y
So the equations are as follows :-
x+y=50.
x= 50-y. (1)
20x+25y=1125p.
4x+5y=225..............(2)
4(50-y)+5y=225
200-4y+5y=225
y=225-200=25
x=25
Hope this will help you and
If you understand then please give a brilliant answer ☺☺
Let the no. of 25 paise coins be y
So the equations are as follows :-
x+y=50.
x= 50-y. (1)
20x+25y=1125p.
4x+5y=225..............(2)
4(50-y)+5y=225
200-4y+5y=225
y=225-200=25
x=25
Hope this will help you and
If you understand then please give a brilliant answer ☺☺
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