Question

A man has only 20paisa coins and 25 paisa coins in his purse lf he has 50 coins in his totalling rs 11.25 how many coins of each kind does he have

Answer 1

Step-by-step explanation:

20,20,5,50

follow me........

Answer 2

$\bold \color{green} { \underline { \underline \red{ \green\star \: required \: answer}}} \star$

Let the number of 20 paisa coins be x and that of 25 paisa coins be y. then,

$\bold{x + y = 50}$

total value of 20 paisa coins = 20x paisa

total value of 25 paisa coins = 25y paisa

$\bold{so \: that \: \: 20x + 25y = 1125 }\\ \bold{ \implies4x + 5y - 225 = 0}$

now by using corss-multiplication, we have

$\bold{\frac{x}{ - 225 + 150} = \frac{ - y}{ - 225 + 20} = \frac{1}{5 - 4} }$

$\bold{\implies \frac{x}{25} = \frac{y}{25} = \frac{1}{1}}$

$\bold{\implies \: x = 25 \: \: and \: y = 25}$

hence, there are 25 coins of each kind..