Question

A man has Rs 21 in the form of 50 paise and 25 paise coins. If the total number of coins are 52, find the number of coins of each type

Answer 1

Answer:

32 coins of 50 paise=16Rs.

20 coins of 25 paise= 5Rs.

Answer 2

$\huge{\blue{\bold{\underline{\underline{Answer :}}}}}$

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$\large{\green{\underline \bold{\tt{Given :-}}}}$

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• A man has Rs 21 in the form of 50 paise and 25 paise coins

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• Total number of coins are 52

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$\large{\red{\underline \bold{\tt{To \: Find :-}}}}$

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• Number of coins of each type

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$\large{\orange{\underline{\tt{Solution :-}}}}$

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• Let the number of 50 paisa coin be "x"

• Let the number of 25 paisa coin be "y"

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$\purple{\underline \bold{According \: to \: the \ question :}}$

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Man has Rs 21 in the form of 50 paise and 25 paise coins

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$\boxed {\bf 1 \ Rs \ = \ 100 \ paisa}$ $\boxed {\bf 21 \ Rs \ = \ 2100 \ paisa}$

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➜ 50x + 25y = 2100

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⟮ Dividing the above equation by "25" ⟯

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➜ 2x + y = 84 --------- (1)

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Also given that total number of coins are 52

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➜ x + y = 52 ----------- (2)

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⟮ Subtracting equation (2) from (1) ⟯

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➜ 2x + y - x - y = 84 - 52

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➨ x = 32 --------- (3)

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• Hence number of 50 paisa coin is 32

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$\underline{\bold{\texttt{Putting x = 32 from (3) to (2) }}}$

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➜ x + y = 52

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➜ 32 + y = 52

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➜ y = 52 - 32

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➨ y = 20

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• Hence number of 25 paisa coin is 20

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∴ Number of 50 paisa and 25 paisa coin are 32 & 20 respectively