Question

A man has Rs 21 in the form of 50 paise and 25 paise coins.If the total no of coins are 52.Find the no of coins of each type

Answer 1

Let 50p = x and 25p = 25 - x
So, 50p = 50x and 25p = 25 X (52 - x)

50x + 1300 - 25x = 2100
50x - 25x = 2100 - 1300
25x = 800
x = 800/25 = 32

50 paise coin = 32
25 paise coin = 52 - 32 = 20

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Answer 2

Answer:

The number of coins 50 paise are 32 and number of coins of 25 paise are 20 .

Step-by-step explanation:

Let us assume that the number of 50 paise coin be x .

Let us assume that the number of 25 paise coin be y .

As given

A man has Rs 21 in the form of 50 paise and 25 paise coins.

As 0.01 Rupee = 1 paise

Than the equation becomes

0.01 × 50x + 0.01 × 25y = 21

Simplify the above

$\frac{50x}{100}+ \frac{25y}{100} = 21$

50x + 25y = 2100

If the total no of coins are 52.

Than the equation becomes

x + y = 52  

Two equations are

x + y = 52  

50x + 25y = 2100

Multiply x + y = 52 by 50 and subtracted from 50x + 25y = 2100 .

50x - 50x + 25y - 50y = 2100 - 2600

-25y = -500

$y = \frac{500}{25}$

y = 20

Putting this value in x + y = 52 .

x + 20 = 52

x = 52 -20

x = 32

Therefore the number of coins 50 paise are 32 and number of coins of 25 paise are 20 .