A man has RS 2100 in the form of 50 rupees and 25 rupees denominations. If the total number of notes is 52, find the number of notes in 50 rupees denomination. *
(a)20
(b)32
(c)42
Answers
Answer:
Hey CUTE!!
Step-by-step explanation:
Let us assume that the number of 50 paise coin be x .
Let us assume that the number of 25 paise coin be y .
As given
A man has Rs 21 in the form of 50 paise and 25 paise coins.
As 0.01 Rupee = 1 paise
Than the equation becomes
0.01 × 50x + 0.01 × 25y = 21
Simplify the above
50x + 25y = 2100
If the total no of coins are 52.
Than the equation becomes
x + y = 52
Two equations are
x + y = 52
50x + 25y = 2100
Multiply x + y = 52 by 50 and subtracted from 50x + 25y = 2100 .
50x - 50x + 25y - 50y = 2100 - 2600
-25y = -500
y = 20
Putting this value in x + y = 52 .
x + 20 = 52
x = 52 -20
x = 32
Therefore the number of coins 50 paise are 32 and number of coins of 25 paise are 20 .
Answer:
The number of 25 paise is 20
The number of 50 paise is 32
Step-by-step explanation:
32+20= 52
50×32= 1600
25×20= 500
1600+500=2100