Question

a man has some buffalows and ducks . if the number of heads is 70 and the number of legs is 200.then the number of buffalows is?

Answer 1

let there be x buffaloes and y ducks

$x + y = 70 = > x = 70 - y$

and

$4x + 2y = 200$

$2x + y = 100$

$2(70 - y) + y = 100$

$140 - 70y + y = 100$

Answer 2

Answer:

The no. of buffaloes is 30

Explanaton:

number of ducks+ buffaloes = 70

therefore,

number of buffaloes = 70 - no. of ducks

therefore, b = 70 - d

putting the value of B in equation no. 2

4(70 - d) + 2d = 200

=> 280-4d+2d=200

=>-2d=200-280

=>2d=80

=> d=40

putting the value of d in no. 1

b+40=70

=>b=70-40

=>b=30

therefore the number of buffaloes with the man is 30

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