A MAN HAS SOME HENS AND COWS .IF THE NUMBER OF HEAD BE 48 AND THE NUMBER OF FEET EQUALS 140FIND THE NUMBER OF HENS AND THE NUMBER OF COWS THAT THE MAN HAS
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these type of questions can be solved by using linear equations in two variables.
step1
let the no of cows be x
no of hens be y
we know that cow has 4 legs and hen has 2 legs but both the animals have only one head.
step2
total no of heads given 48
total no of heads in variable form is x+y
so x+y=48
one cow has 4 legs
total x cows then total no of cow legs are4×x i.e 4x similarly hens total no of hen legs are 2y
then total no of legs 4x+2y in variable form
given total no of legs are 140
step3
the two equations are x+y=48
4x+2y=140
on solving both equations we get x=22, y=26
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