Question

A man has strayed from his path while on his way to the park he moves 100km towards south m then another 40km towqrdswest he then travels 70km towards north and reafhes the park.what is the distance of the shortest possible route

Answer 1

From the attached diagram, the man moved from A to B to C and finally to D, the park.

The shortest distance is AD

DE = BC = 40km

AE = 100 - 70 = 30 km

By Pythagoras theorem;

AD² = AE² + DE²

AD² = 30² + 40²

AD² = 900 + 1600

AD² = 2500

AD = 50

The shortest distance = 50 km

Answer 2

Answer:

Step-by-step explanation: