Question

A man has strayed from his path while on his way to the park. He moves 100km towards south, then another 40km towards west. He then travels 70km towards north and reaches the park. What is the distance to the shortest possible route?

Answer 1

use Pythagoras theorem
(100-70)^2 +40^2= side^2
=30^2 +40^2
=900+1600
=2500
hence side is √2500
=50km

Answer 2

Answer:

50 km

Step-by-step explanation:

firstly man go to south and then turn towards west and after that north

it means he covered back some position toward starting point.

so his total traveled distance in south direction=(100-70)km

=30 km

his total traveled distance in west direction=40 km

to find shortest distance (let x), we use pythagoras theorem

x²=30²+40²

⇒x²=900+1600

⇒x²=2500

⇒x=50 km

so the shortest distance is 50 km from his starting point.