a man has to exert a force of 10 Newton at the edge of the door to put it open, how much force will the man have to exert if he pushes the centre of the door?
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Answer:
20 N
Step-by-step explanation:
Let the distance between hinge and edge be "L"
The torque needed to open the door when force applied on edge is
T = Force × Perpendicular distance
= 10 Newton × L
= 10L
Then, the force is applied at the centre. To get the same torque the force "F" needed is
10L = F × L/2
F = 20 Newtons
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