Question

a man has to travel 50km in two hours. he could cover 20 kms in one hour. and then had to stop for 20 minutes for refueling. by what factor should he increase his speed with reference to that during the four hours so as to be able to complete the journey as per schedule?

Answer 1

Step-by-step explanation:

Answer:

1.8

Step-by-step explanation:

total time he has = 2 hrs

total distance he has to covered = 50 km

in first 1 hr he completed 20 km

so S1= 20 km/hr

so remaining distance = 50-20 = 30 Km

and remaining time = 1 hr

now he spent 10 minutes for refueling

so total remaining time he has = 60-10 = 50 minutes

he has to complete 30 km in this time

speed = 30\(10/60) km/hr

speed = 36 km/hr

for making a factor of initial speed as 20 km/hr

multiply 36 with 20/20

speed = 36x(20/20)

=(1.8x S1 )km\hr

= 1.8 km/hr ---- Ans (As S1 is 20km/hr)

Answer 2

Answer:

Hope you mark it as brainilist