Question

A man having spent 3/5th of his money found that he had ₹290 left. How much had he at first? ​

Answer 1

Answer:

The man had Rs. 725 at first

Step-by-step explanation:

Let the man had Rs. x initially.

$money \: spent \: = \: rs. \: \frac{3x}{5}$

$∴money \: left \: = \: rs. \: (x - \frac{3x}{5} )$

$∴money \: \: left \: = \: rs. \: \frac{2x}{5}$

According to the question,

$\frac{2x}{5} = rs. \: 290$

$∴x = rs. \: (290 \times \frac{5}{2} ) = rs. \: 725$

∴ The man first had Rs. 725

Hope this helps you :)

Answer 2

Answer:

₹725

Step-by-step explanation:

Step 1:

Assign all letters to numbers

let x = how much money he had first

Step 2:

Interpret the question and solve

Since he spent 3/5 of x,

His money - what he spent = his money left

x                 -  3/5 of x            =  290

Multiply all through by 5 to eliminate the denominator

(x·5)  - [(3x / 5) · 5] = 290 · 5

5x - 3x = 1450

2x = 1450

Divide both sides by the coefficient of x which is 2

2x/2 = 1450/2

x = 725

So remember is said x = how much money he had first

∴ he had ₹725 at first