A man height of 156cm stands under semicircular arc at a distance of 36cm from one end such that his head touches the arc.find arc width
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Given A man of height 156 cm stands under a semi-circular arc at a distance of 36 cm from one end such that it touches the arc. Find the width of arc.
- Applying Pythagoras theorem we get ( r – 36 is base , height is 156 cm and we need to find opposite side r)
- So r^2 = 156^2 + (r – 36)^2
- So r^2 = 156^2 + r^2 + 36^2 – 2 (36) r
- So r^2 = 156^2 + r^2 + 36^2 – 72 r
- So 72 r = 156^2 + 36^2
- 72 r = 25,632
- Or r = 25,632 / 72
- Or r = 356 cm
- We know that diameter d = 2 r
- Or d = 2 x 356
- Or d = 712 cm
Reference link will be
https://brainly.in/question/15895622
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