Question

a man holding a flag is running in north east direction with speed 10 metre per second wind is blowing in east direction with speed 5 root 2 metre per second find the direction in which flag will flutter

Answer 1

Answer is-
Calculate the direction of the resultant or the angle a, between the wind velocity vector and the resultant.
the angle between the two vectors, the velocity of wind and the flag would be 90 + 45 = 135 deg.
so,
tanα = (velocity of flag X sin135) / [velocity of wind + (velocity of flag X cos135)) tanα = 10sin135 / (5V2 + cos135) or tanα = infinity thus, the angle between resultant and wind = 90 degrees,
So, the flag will flow directly south.

Answer 2

Answer:

Explanation:

Have a look at the figure below

As the man runs in the north-eastern direction the flag flutters in the opposite direction, south-west, as shown. The wind blows directly east...

we need to calculate the direction of the resultant or the angle α, between the wind velocity vector and the resultant.

the angle between th two vectors, velocity of wind and the flag would be 90 + 45 = 135 deg.

so,

tanα = (velocity of flag X sin135) / [velocity of wind + (velocity of flag X cos135)]

tanα = 10sin135 / (5√2 + cos135)

or

tanα = infinity

thus, the angle between resultant and wind = 90 degrees,

So, the flag will flow directly south, as shown in the figure