A man holding a sack and barrow stationary.he applies vertical force on d handle.the center of mass and weight of sack are shown.wheel acts as pivot
Answers
Answer:
Sorry but where is the pic or attachments
Complete question:
The diagram shows a man holding a sack and barrow stationary. He applies a vertical force to the handle. The center of mass and the weight of the sack and barrow are shown. The wheel acts as a pivot. What is the magnitude of the vertical force exerted by the man?
Answer:
The magnitude of the vertical force exerted by the man is 50 N.
Explanation:
Let the vertical force applied by the man be 'F'
Given,
The center of mass of the sack and barrow is 200 N
To find,
The force applied by the man 'F'.
Calculation,
As the whole setup is stationary.
We apply torque at the wheel which acts as a pivot.
The torque due to center of mass (T₁) = 15 cm × 200 N
The torque due to vertical force (T₂) = (45 + 15) cm × F = 60 cm × F
For equilibrium condition:
T₁ = T₂
⇒ 15 cm × 200 N = 60 cm × F
⇒ F = 50 N
therefore, the magnitude of the vertical force exerted by the man is 50 N.
#SPJ3
