Question

A man holding a sack and barrow stationary.he applies vertical force on d handle.the center of mass and weight of sack are shown.wheel acts as pivot

Answer 1

Answer:

Sorry but where is the pic or attachments

Answer 2

Complete question:

The diagram shows a man holding a sack and barrow stationary. He applies a vertical force to the handle. The center of mass and the weight of the sack and barrow are shown. The wheel acts as a pivot. What is the magnitude of the vertical force exerted by the man?

Answer:

The magnitude of the vertical force exerted by the man is 50 N.

Explanation:

Let the vertical force applied by the man be 'F'

Given,

The center of mass of the sack and barrow is 200 N

To find,

The force applied by the man 'F'.

Calculation,

As the whole setup is stationary.

We apply torque at the wheel which acts as a pivot.

The torque due to center of mass (T₁) = 15 cm × 200 N

The torque due to vertical force (T₂) = (45 + 15) cm × F = 60 cm × F

For equilibrium condition:

T₁ = T₂

⇒ 15 cm × 200 N = 60 cm × F

⇒ F = 50 N

therefore, the magnitude of the vertical force exerted by the man is 50 N.

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